“Passing types, operators and the labyrinth of expression” theft by finding
In this statement "We checked on the table-code sequences that '\ 007,' as a character, length of 4. Issue this time, why not the compilers' \ 007 'as' \ 0'' 0''7 '? If this is the case for the length of 0, we were dead and split the symbols, Oh, and this is a concrete realization of the compiler associated with our existing knowledge can not be understood this point, leaving to stay the pending "realized" day bar, believe me, this is a real pleasure. "is not necessary Jones, a compiler theory, where lexical scanner will find \ 007 is not an escape character \ 0 07 .
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On Open source @ 31/12/2006 | By admin
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